(3)/(4)y^2-(1)/(2)y=(5)/(8)

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Solution for (3)/(4)y^2-(1)/(2)y=(5)/(8) equation: 


y in (-oo:+oo)

(3/4)*y^2-((1/2)*y) = 5/8 // - 5/8

(3/4)*y^2-((1/2)*y)-(5/8) = 0

(3/4)*y^2+(-1/2)*y-5/8 = 0

3/4*y^2-1/2*y-5/8 = 0

DELTA = (-1/2)^2-(-5/8*3/4*4)

DELTA = 17/8

DELTA > 0

y = ((17/8)^(1/2)+1/2)/(3/4*2) or y = (1/2-(17/8)^(1/2))/(3/4*2)

y = 2/3*((17/8)^(1/2)+1/2) or y = 2/3*(1/2-(17/8)^(1/2))

y in { 2/3*(1/2-(17/8)^(1/2)), 2/3*((17/8)^(1/2)+1/2) }

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